2x^2+2x-18=-12x+x+x^2

Solution for 2x^2+2x-18=-12x+x+x^2 equation:

2x^2+2x-18=-12x+x+x^2

We move all terms to the left:

2x^2+2x-18-(-12x+x+x^2)=0

We get rid of parentheses

2x^2-x^2+12x-x+2x-18=0

We add all the numbers together, and all the variables

x^2+13x-18=0

a = 1; b = 13; c = -18;
Δ = b2-4ac
Δ = 132-4·1·(-18)
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{241}}{2*1}=\frac{-13-\sqrt{241}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{241}}{2*1}=\frac{-13+\sqrt{241}}{2}
$